(x^2+1)(2x^2-x-1)=0

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Solution for (x^2+1)(2x^2-x-1)=0 equation:


Simplifying
(x2 + 1)(2x2 + -1x + -1) = 0

Reorder the terms:
(1 + x2)(2x2 + -1x + -1) = 0

Reorder the terms:
(1 + x2)(-1 + -1x + 2x2) = 0

Multiply (1 + x2) * (-1 + -1x + 2x2)
(1(-1 + -1x + 2x2) + x2(-1 + -1x + 2x2)) = 0
((-1 * 1 + -1x * 1 + 2x2 * 1) + x2(-1 + -1x + 2x2)) = 0
((-1 + -1x + 2x2) + x2(-1 + -1x + 2x2)) = 0
(-1 + -1x + 2x2 + (-1 * x2 + -1x * x2 + 2x2 * x2)) = 0
(-1 + -1x + 2x2 + (-1x2 + -1x3 + 2x4)) = 0

Combine like terms: 2x2 + -1x2 = 1x2
(-1 + -1x + 1x2 + -1x3 + 2x4) = 0

Solving
-1 + -1x + 1x2 + -1x3 + 2x4 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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